y=(2/3)x^2+3

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Solution for y=(2/3)x^2+3 equation: 


x in (-oo:+oo)

y = (2/3)*x^2+3 // - (2/3)*x^2+3

y-((2/3)*x^2)-3 = 0

(-2/3)*x^2+y-3 = 0

-2/3*x^2 = -(y-3) // : -2/3

x^2 = -3/2*(3-y)

x^2 = -3/2*(3-y) // ^ 1/2

abs(x) = (-3/2)^(1/2)*(3-y)^(1/2)

x = (-3/2)^(1/2)*(3-y)^(1/2) or x = -((-3/2)^(1/2)*(3-y)^(1/2))

x in { (-3/2)^(1/2)*(3-y)^(1/2), -((-3/2)^(1/2)*(3-y)^(1/2)) }

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